Try to convert pow(X, 1.50) --> X * sqrt(X) and Pow(X,(2/3)) to cube root of (X*X).
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Details
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Differential D94543
[DAGCombine] Optimize pow(X, (2/3)) and Pow(X,(3/2)) GGanesh on Jan 12 2021, 12:33 PM. Authored by
Details Try to convert pow(X, 1.50) --> X * sqrt(X) and Pow(X,(2/3)) to cube root of (X*X).
Diff Detail
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