[compiler-rt] Disable a test failing on windows.

[etienneb]

Summary

The unittest is not working on windows. The "regexp.h" is not available and
gtest-port won't support regexp with operator '|'.

The test wasn't failing on 32-bits because of this check:

if (SANITIZER_WORDSIZE != 64 || ASAN_AVOID_EXPENSIVE_TESTS) return;

[ RUN      ] AddressSanitizer.HugeMallocTest
C:/src/llvm/llvm/utils/unittest/googletest\src/gtest-port.cc(272): error: Failed
Syntax error at index 30 in simple regular expression "is located 1 bytes to the left|AddressSanitizer failed to allocate": '|' is unsupported.
C:/src/llvm/llvm/projects/compiler-rt/lib/asan/tests/asan_test.cc(308): error: Death test: Ident((char*)malloc(n_megs << 20))[-1] = 0
    Result: died but not with expected error.
  Expected: is located 1 bytes to the left|AddressSanitizer failed to allocate

See gtest-port.h:

  #elif GTEST_OS_WINDOWS

// <regex.h> is not available on Windows.  Use our own simple regex
// implementation instead.
# define GTEST_USES_SIMPLE_RE 1

[rnk]

lgtm

lib/asan/tests/asan_test.cc

 
 TEST(AddressSanitizer, LargeMallocTest) {
   const int max_size = (SANITIZER_WORDSIZE == 32) ? 1 << 26 : 1 << 28;
   for (int i = 113; i < max_size; i = i * 2 + 13) {
     TestLargeMalloc(i);
   }
 }
 
+#if !GTEST_USES_SIMPLE_RE
 TEST(AddressSanitizer, HugeMallocTest) {
   if (SANITIZER_WORDSIZE != 64 || ASAN_AVOID_EXPENSIVE_TESTS) return;
   size_t n_megs = 4100;
   EXPECT_DEATH(Ident((char*)malloc(n_megs << 20))[-1] = 0,
                "is located 1 bytes to the left|"
                "AddressSanitizer failed to allocate");
 }
+#endif
 
 #if SANITIZER_TEST_HAS_MEMALIGN
 void MemalignRun(size_t align, size_t size, int idx) {
   char *p = (char *)memalign(align, size);
   Ident(p)[idx] = 0;
   free(p);
 }