https://wg21.link/LWG2444 updated the comparison complexity of
std:sort_heap to be at most 2N log (N) where N == last - first. In the current implementation, we invoke __pop_heap exactly N-1 times. In each call to __pop_heap, we first go down the heap from first to possibly last in the function __floyd_sift_down. Then, we possibly go back up in the function __sift_up. In the function __floyd_sift_down, there is loop in which one comparison is made in each iteration. The loop runs till __child becomes greater than (__len - 2) / 2. __child starts at 0 and it is at least set to 2 * __child + 1 on each iteration. Thus, after k iterations, __child will be at least 2^k - 1. After log(N) iterations, __child >= 2^(log(N)) - 1 = N - 1 > (__len - 2) / 2. This means that the while loop in the function __floyd_sift_down would perform at most log(N) comparisons on each invocation. In the function __sift_up, there is one comparison made that will almost always occur. After that there is a do-while loop. The comparison function is invoked once in each iteration. In the worst case, the loop will run till __len goes down to zero. It can start from (N-3)/2. In each iteration, __len goes down to (__len-1) / 2. After k iterations, __len will be at most (N - 2^(k+1) -1) / 2^(k+1). Thus, __len will become when (N-2^(k+1)-1) < 2^(k+1) i.e. N < 2^(k+2) + 1. This means at most log(N) - 1 iterations for the loop. So in total at most log(N) comparison will be performed in __sift_up. So overall for each iteration of the loop in __pop_heap, there will at most 2 log(N) comparisons. So, the total number of comparisons is at most 2 N log(N).
Could you move this test to libcxx/test/std and also add it to ranges_sort_heap.pass.cpp?