[sanitizers] Remove the test case involving `new int[0]`

[oontvoo]

Summary

Bionic doesn't acutally allocate any memory in this case, so there won't be a leak on Android.

[vitalybuka]

compiler-rt/test/asan/TestCases/leaks.cpp

25

other platform allocate stuff, so maybe just something here like this
if (ANDROID && n == 0) n = 1;

[vitalybuka]

LGTM with the change

[oontvoo]

put back the //RUN and re-adjust n from 0 to 1 at runtime

compiler-rt/test/asan/TestCases/leaks.cpp

 // Test for LeakSanitizer+AddressSanitizer of different sizes.
 // REQUIRES: leak-detection
 //
 // RUN: %clangxx_asan -O0 %s -o %t
 // RUN: not %run %t 0 2>&1 | FileCheck %s
 // RUN: not %run %t 1 2>&1 | FileCheck %s
 // RUN: not %run %t 1000 2>&1 | FileCheck %s
 // RUN: not %run %t 1000000 2>&1 | FileCheck %s
 // RUN: not %run %t 10000000 2>&1 | FileCheck %s
 
 #include <cstdlib>
 #include <stdio.h>
 #include <thread>
 int *t;
 
 __attribute__((noopt)) void leak(int n) {
+#if defined(__ANDROID__) || defined(__BIONIC__)
+  // Bionic does not acutally allocate when n==0, hence
+  // there would not be a leak.
+  // Re-adjust n so the test can pass.
+  if (n == 0)
+    n = 1;
+#endif
+
   // Repeat few times to make sure that at least one pointer is
   // not somewhere on the stack.
   for (int i = 0; i < 10; ++i) {
     t = new int[n];
     printf("t: %p\n", t);
     t = 0;
   }
 }
 
 int main(int argc, char **argv) {
   leak(atoi(argv[1]));
 }
 // CHECK: LeakSanitizer: detected memory leaks