__use() can't be marked as constexpr in C++11 because it returns void,
which is not a literal type. But it turns out that we just don't need
to define it at all, since it's never called outside of decltype.
Details
Details
- Reviewers
philnik - Group Reviewers
Restricted Project - Commits
- rG867c966c7d1f: [libc++] Fix __verbose_abort in C++11
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Diff Detail
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