Indentation Correction

[sonamkumari]

Summary

Hi,

I corrected the indentation of the "if" condition in InstCombineMulDivRem.cpp file.
Please help in reviewing.

Regards,
Sonam.

[suyog]

LGTM.

[suyog]

Closed by commit rL219203 (authored by @suyog).

lib/Transforms/InstCombine/InstCombineMulDivRem.cpp

 }
 
 // X udiv 2^C -> X >> C
 static Instruction *foldUDivPow2Cst(Value *Op0, Value *Op1,
                                     const BinaryOperator &I, InstCombiner &IC) {
   const APInt &C = cast<Constant>(Op1)->getUniqueInteger();
   BinaryOperator *LShr = BinaryOperator::CreateLShr(
       Op0, ConstantInt::get(Op0->getType(), C.logBase2()));
-  if (I.isExact()) LShr->setIsExact();
+  if (I.isExact())
+    LShr->setIsExact();
   return LShr;
 }
 
 // X udiv C, where C >= signbit
 static Instruction *foldUDivNegCst(Value *Op0, Value *Op1,
                                    const BinaryOperator &I, InstCombiner &IC) {
   Value *ICI = IC.Builder->CreateICmpULT(Op0, cast<ConstantInt>(Op1));
 
static Instruction *foldUDivShl(Value *Op0, Value *Op1, const BinaryOperator &I,
   const APInt &CI =
       cast<Constant>(ShiftLeft->getOperand(0))->getUniqueInteger();
   Value *N = ShiftLeft->getOperand(1);
   if (CI != 1)
     N = IC.Builder->CreateAdd(N, ConstantInt::get(N->getType(), CI.logBase2()));
   if (ZExtInst *Z = dyn_cast<ZExtInst>(Op1))
     N = IC.Builder->CreateZExt(N, Z->getDestTy());
   BinaryOperator *LShr = BinaryOperator::CreateLShr(Op0, N);
-  if (I.isExact()) LShr->setIsExact();
+  if (I.isExact())
+    LShr->setIsExact();
   return LShr;
 }
 
 // \brief Recursively visits the possible right hand operands of a udiv
 // instruction, seeing through select instructions, to determine if we can
 // replace the udiv with something simpler.  If we find that an operand is not
 // able to simplify the udiv, we abort the entire transformation.
 static size_t visitUDivOperand(Value *Op0, Value *Op1, const BinaryOperator &I,