If we have a store to a piece of memory which is known constant, then we know the store must be storing back the same value. As a result, the store (or memset, or memmove) must either be down a dead path, or a noop. In either case, it is valid to simply remove the store.
The motivating case for this involves a memmove to a buffer which is constant down a path which is dynamically dead.
Note that I'm choosing to implement the less aggressive of two possible semantics here. We could simply say that the store *is undefined*, and prune the path. That seemed a bit too likely to break real code in subtle ways, so I decide to just remove the store itself.
(I'm going to rebase the tests shortly, so you can ignore the spurious diffs. I'll rebase once done.)