Index: llvm/include/llvm/Support/SuffixTree.h =================================================================== --- /dev/null +++ llvm/include/llvm/Support/SuffixTree.h @@ -0,0 +1,350 @@ +//===- llvm/ADT/SuffixTree.h - Tree for substrings --------------*- C++ -*-===// +// +// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. +// See https://llvm.org/LICENSE.txt for license information. +// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception +// +//===----------------------------------------------------------------------===// +// +// This file defines the Suffix Tree class and Suffix Tree Node struct. +// +//===----------------------------------------------------------------------===// +#ifndef LLVM_SUPPORT_SUFFIXTREE_H +#define LLVM_SUPPORT_SUFFIXTREE_H + +#include "llvm/ADT/ArrayRef.h" +#include "llvm/ADT/DenseMap.h" +#include "llvm/Support/Allocator.h" +#include + +namespace llvm { + +/// Represents an undefined index in the suffix tree. +const unsigned EmptyIdx = -1; + +/// A node in a suffix tree which represents a substring or suffix. +/// +/// Each node has either no children or at least two children, with the root +/// being a exception in the empty tree. +/// +/// Children are represented as a map between unsigned integers and nodes. If +/// a node N has a child M on unsigned integer k, then the mapping represented +/// by N is a proper prefix of the mapping represented by M. Note that this, +/// although similar to a trie is somewhat different: each node stores a full +/// substring of the full mapping rather than a single character state. +/// +/// Each internal node contains a pointer to the internal node representing +/// the same string, but with the first character chopped off. This is stored +/// in \p Link. Each leaf node stores the start index of its respective +/// suffix in \p SuffixIdx. +struct SuffixTreeNode { + + /// The children of this node. + /// + /// A child existing on an unsigned integer implies that from the mapping + /// represented by the current node, there is a way to reach another + /// mapping by tacking that character on the end of the current string. + llvm::DenseMap Children; + + /// The start index of this node's substring in the main string. + unsigned StartIdx = EmptyIdx; + + /// The end index of this node's substring in the main string. + /// + /// Every leaf node must have its \p EndIdx incremented at the end of every + /// step in the construction algorithm. To avoid having to update O(N) + /// nodes individually at the end of every step, the end index is stored + /// as a pointer. + unsigned *EndIdx = nullptr; + + /// For leaves, the start index of the suffix represented by this node. + /// + /// For all other nodes, this is ignored. + unsigned SuffixIdx = EmptyIdx; + + /// For internal nodes, a pointer to the internal node representing + /// the same sequence with the first character chopped off. + /// + /// This acts as a shortcut in Ukkonen's algorithm. One of the things that + /// Ukkonen's algorithm does to achieve linear-time construction is + /// keep track of which node the next insert should be at. This makes each + /// insert O(1), and there are a total of O(N) inserts. The suffix link + /// helps with inserting children of internal nodes. + /// + /// Say we add a child to an internal node with associated mapping S. The + /// next insertion must be at the node representing S - its first character. + /// This is given by the way that we iteratively build the tree in Ukkonen's + /// algorithm. The main idea is to look at the suffixes of each prefix in the + /// string, starting with the longest suffix of the prefix, and ending with + /// the shortest. Therefore, if we keep pointers between such nodes, we can + /// move to the next insertion point in O(1) time. If we don't, then we'd + /// have to query from the root, which takes O(N) time. This would make the + /// construction algorithm O(N^2) rather than O(N). + SuffixTreeNode *Link = nullptr; + + /// The length of the string formed by concatenating the edge labels from the + /// root to this node. + unsigned ConcatLen = 0; + + /// Returns true if this node is a leaf. + bool isLeaf() const { return SuffixIdx != EmptyIdx; } + + /// Returns true if this node is the root of its owning \p SuffixTree. + bool isRoot() const { return StartIdx == EmptyIdx; } + + /// Return the number of elements in the substring associated with this node. + size_t size() const { + + // Is it the root? If so, it's the empty string so return 0. + if (isRoot()) + return 0; + + assert(*EndIdx != EmptyIdx && "EndIdx is undefined!"); + + // Size = the number of elements in the string. + // For example, [0 1 2 3] has length 4, not 3. 3-0 = 3, so we have 3-0+1. + return *EndIdx - StartIdx + 1; + } + + SuffixTreeNode(unsigned StartIdx, unsigned *EndIdx, SuffixTreeNode *Link) + : StartIdx(StartIdx), EndIdx(EndIdx), Link(Link) {} + + SuffixTreeNode() {} +}; + +/// A data structure for fast substring queries. +/// +/// Suffix trees represent the suffixes of their input strings in their leaves. +/// A suffix tree is a type of compressed trie structure where each node +/// represents an entire substring rather than a single character. Each leaf +/// of the tree is a suffix. +/// +/// A suffix tree can be seen as a type of state machine where each state is a +/// substring of the full string. The tree is structured so that, for a string +/// of length N, there are exactly N leaves in the tree. This structure allows +/// us to quickly find repeated substrings of the input string. +/// +/// In this implementation, a "string" is a vector of unsigned integers. +/// These integers may result from hashing some data type. A suffix tree can +/// contain 1 or many strings, which can then be queried as one large string. +/// +/// The suffix tree is implemented using Ukkonen's algorithm for linear-time +/// suffix tree construction. Ukkonen's algorithm is explained in more detail +/// in the paper by Esko Ukkonen "On-line construction of suffix trees. The +/// paper is available at +/// +/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf +class SuffixTree { +public: + /// Each element is an integer representing an instruction in the module. + llvm::ArrayRef Str; + + /// A repeated substring in the tree. + struct RepeatedSubstring { + /// The length of the string. + unsigned Length; + + /// The start indices of each occurrence. + std::vector StartIndices; + }; + +private: + /// Maintains each node in the tree. + llvm::SpecificBumpPtrAllocator NodeAllocator; + + /// The root of the suffix tree. + /// + /// The root represents the empty string. It is maintained by the + /// \p NodeAllocator like every other node in the tree. + SuffixTreeNode *Root = nullptr; + + /// Maintains the end indices of the internal nodes in the tree. + /// + /// Each internal node is guaranteed to never have its end index change + /// during the construction algorithm; however, leaves must be updated at + /// every step. Therefore, we need to store leaf end indices by reference + /// to avoid updating O(N) leaves at every step of construction. Thus, + /// every internal node must be allocated its own end index. + llvm::BumpPtrAllocator InternalEndIdxAllocator; + + /// The end index of each leaf in the tree. + unsigned LeafEndIdx = -1; + + /// Helper struct which keeps track of the next insertion point in + /// Ukkonen's algorithm. + struct ActiveState { + /// The next node to insert at. + SuffixTreeNode *Node = nullptr; + + /// The index of the first character in the substring currently being added. + unsigned Idx = EmptyIdx; + + /// The length of the substring we have to add at the current step. + unsigned Len = 0; + }; + + /// The point the next insertion will take place at in the + /// construction algorithm. + ActiveState Active; + + /// Allocate a leaf node and add it to the tree. + /// + /// \param Parent The parent of this node. + /// \param StartIdx The start index of this node's associated string. + /// \param Edge The label on the edge leaving \p Parent to this node. + /// + /// \returns A pointer to the allocated leaf node. + SuffixTreeNode *insertLeaf(SuffixTreeNode &Parent, unsigned StartIdx, + unsigned Edge); + + /// Allocate an internal node and add it to the tree. + /// + /// \param Parent The parent of this node. Only null when allocating the root. + /// \param StartIdx The start index of this node's associated string. + /// \param EndIdx The end index of this node's associated string. + /// \param Edge The label on the edge leaving \p Parent to this node. + /// + /// \returns A pointer to the allocated internal node. + SuffixTreeNode *insertInternalNode(SuffixTreeNode *Parent, unsigned StartIdx, + unsigned EndIdx, unsigned Edge); + + /// Set the suffix indices of the leaves to the start indices of their + /// respective suffixes. + void setSuffixIndices(); + + /// Construct the suffix tree for the prefix of the input ending at + /// \p EndIdx. + /// + /// Used to construct the full suffix tree iteratively. At the end of each + /// step, the constructed suffix tree is either a valid suffix tree, or a + /// suffix tree with implicit suffixes. At the end of the final step, the + /// suffix tree is a valid tree. + /// + /// \param EndIdx The end index of the current prefix in the main string. + /// \param SuffixesToAdd The number of suffixes that must be added + /// to complete the suffix tree at the current phase. + /// + /// \returns The number of suffixes that have not been added at the end of + /// this step. + unsigned extend(unsigned EndIdx, unsigned SuffixesToAdd); + +public: + /// Construct a suffix tree from a sequence of unsigned integers. + /// + /// \param Str The string to construct the suffix tree for. + SuffixTree(const std::vector &Str); + + /// Iterator for finding all repeated substrings in the suffix tree. + struct RepeatedSubstringIterator { + private: + /// The current node we're visiting. + SuffixTreeNode *N = nullptr; + + /// The repeated substring associated with this node. + RepeatedSubstring RS; + + /// The nodes left to visit. + std::vector ToVisit; + + /// The minimum length of a repeated substring to find. + /// Since we're outlining, we want at least two instructions in the range. + /// FIXME: This may not be true for targets like X86 which support many + /// instruction lengths. + const unsigned MinLength = 2; + + /// Move the iterator to the next repeated substring. + void advance() { + // Clear the current state. If we're at the end of the range, then this + // is the state we want to be in. + RS = RepeatedSubstring(); + N = nullptr; + + // Each leaf node represents a repeat of a string. + std::vector LeafChildren; + + // Continue visiting nodes until we find one which repeats more than once. + while (!ToVisit.empty()) { + SuffixTreeNode *Curr = ToVisit.back(); + ToVisit.pop_back(); + LeafChildren.clear(); + + // Keep track of the length of the string associated with the node. If + // it's too short, we'll quit. + unsigned Length = Curr->ConcatLen; + + // Iterate over each child, saving internal nodes for visiting, and + // leaf nodes in LeafChildren. Internal nodes represent individual + // strings, which may repeat. + for (auto &ChildPair : Curr->Children) { + // Save all of this node's children for processing. + if (!ChildPair.second->isLeaf()) + ToVisit.push_back(ChildPair.second); + + // It's not an internal node, so it must be a leaf. If we have a + // long enough string, then save the leaf children. + else if (Length >= MinLength) + LeafChildren.push_back(ChildPair.second); + } + + // The root never represents a repeated substring. If we're looking at + // that, then skip it. + if (Curr->isRoot()) + continue; + + // Do we have any repeated substrings? + if (LeafChildren.size() >= 2) { + // Yes. Update the state to reflect this, and then bail out. + N = Curr; + RS.Length = Length; + for (SuffixTreeNode *Leaf : LeafChildren) + RS.StartIndices.push_back(Leaf->SuffixIdx); + break; + } + } + + // At this point, either NewRS is an empty RepeatedSubstring, or it was + // set in the above loop. Similarly, N is either nullptr, or the node + // associated with NewRS. + } + + public: + /// Return the current repeated substring. + RepeatedSubstring &operator*() { return RS; } + + RepeatedSubstringIterator &operator++() { + advance(); + return *this; + } + + RepeatedSubstringIterator operator++(int I) { + RepeatedSubstringIterator It(*this); + advance(); + return It; + } + + bool operator==(const RepeatedSubstringIterator &Other) { + return N == Other.N; + } + bool operator!=(const RepeatedSubstringIterator &Other) { + return !(*this == Other); + } + + RepeatedSubstringIterator(SuffixTreeNode *N) : N(N) { + // Do we have a non-null node? + if (N) { + // Yes. At the first step, we need to visit all of N's children. + // Note: This means that we visit N last. + ToVisit.push_back(N); + advance(); + } + } + }; + + typedef RepeatedSubstringIterator iterator; + iterator begin() { return iterator(Root); } + iterator end() { return iterator(nullptr); } +}; + +} // namespace llvm + +#endif // LLVM_SUPPORT_SUFFIXTREE_H Index: llvm/lib/CodeGen/MachineOutliner.cpp =================================================================== --- llvm/lib/CodeGen/MachineOutliner.cpp +++ llvm/lib/CodeGen/MachineOutliner.cpp @@ -70,9 +70,9 @@ #include "llvm/IR/IRBuilder.h" #include "llvm/IR/Mangler.h" #include "llvm/InitializePasses.h" -#include "llvm/Support/Allocator.h" #include "llvm/Support/CommandLine.h" #include "llvm/Support/Debug.h" +#include "llvm/Support/SuffixTree.h" #include "llvm/Support/raw_ostream.h" #include #include @@ -107,513 +107,6 @@ namespace { -/// Represents an undefined index in the suffix tree. -const unsigned EmptyIdx = -1; - -/// A node in a suffix tree which represents a substring or suffix. -/// -/// Each node has either no children or at least two children, with the root -/// being a exception in the empty tree. -/// -/// Children are represented as a map between unsigned integers and nodes. If -/// a node N has a child M on unsigned integer k, then the mapping represented -/// by N is a proper prefix of the mapping represented by M. Note that this, -/// although similar to a trie is somewhat different: each node stores a full -/// substring of the full mapping rather than a single character state. -/// -/// Each internal node contains a pointer to the internal node representing -/// the same string, but with the first character chopped off. This is stored -/// in \p Link. Each leaf node stores the start index of its respective -/// suffix in \p SuffixIdx. -struct SuffixTreeNode { - - /// The children of this node. - /// - /// A child existing on an unsigned integer implies that from the mapping - /// represented by the current node, there is a way to reach another - /// mapping by tacking that character on the end of the current string. - DenseMap Children; - - /// The start index of this node's substring in the main string. - unsigned StartIdx = EmptyIdx; - - /// The end index of this node's substring in the main string. - /// - /// Every leaf node must have its \p EndIdx incremented at the end of every - /// step in the construction algorithm. To avoid having to update O(N) - /// nodes individually at the end of every step, the end index is stored - /// as a pointer. - unsigned *EndIdx = nullptr; - - /// For leaves, the start index of the suffix represented by this node. - /// - /// For all other nodes, this is ignored. - unsigned SuffixIdx = EmptyIdx; - - /// For internal nodes, a pointer to the internal node representing - /// the same sequence with the first character chopped off. - /// - /// This acts as a shortcut in Ukkonen's algorithm. One of the things that - /// Ukkonen's algorithm does to achieve linear-time construction is - /// keep track of which node the next insert should be at. This makes each - /// insert O(1), and there are a total of O(N) inserts. The suffix link - /// helps with inserting children of internal nodes. - /// - /// Say we add a child to an internal node with associated mapping S. The - /// next insertion must be at the node representing S - its first character. - /// This is given by the way that we iteratively build the tree in Ukkonen's - /// algorithm. The main idea is to look at the suffixes of each prefix in the - /// string, starting with the longest suffix of the prefix, and ending with - /// the shortest. Therefore, if we keep pointers between such nodes, we can - /// move to the next insertion point in O(1) time. If we don't, then we'd - /// have to query from the root, which takes O(N) time. This would make the - /// construction algorithm O(N^2) rather than O(N). - SuffixTreeNode *Link = nullptr; - - /// The length of the string formed by concatenating the edge labels from the - /// root to this node. - unsigned ConcatLen = 0; - - /// Returns true if this node is a leaf. - bool isLeaf() const { return SuffixIdx != EmptyIdx; } - - /// Returns true if this node is the root of its owning \p SuffixTree. - bool isRoot() const { return StartIdx == EmptyIdx; } - - /// Return the number of elements in the substring associated with this node. - size_t size() const { - - // Is it the root? If so, it's the empty string so return 0. - if (isRoot()) - return 0; - - assert(*EndIdx != EmptyIdx && "EndIdx is undefined!"); - - // Size = the number of elements in the string. - // For example, [0 1 2 3] has length 4, not 3. 3-0 = 3, so we have 3-0+1. - return *EndIdx - StartIdx + 1; - } - - SuffixTreeNode(unsigned StartIdx, unsigned *EndIdx, SuffixTreeNode *Link) - : StartIdx(StartIdx), EndIdx(EndIdx), Link(Link) {} - - SuffixTreeNode() {} -}; - -/// A data structure for fast substring queries. -/// -/// Suffix trees represent the suffixes of their input strings in their leaves. -/// A suffix tree is a type of compressed trie structure where each node -/// represents an entire substring rather than a single character. Each leaf -/// of the tree is a suffix. -/// -/// A suffix tree can be seen as a type of state machine where each state is a -/// substring of the full string. The tree is structured so that, for a string -/// of length N, there are exactly N leaves in the tree. This structure allows -/// us to quickly find repeated substrings of the input string. -/// -/// In this implementation, a "string" is a vector of unsigned integers. -/// These integers may result from hashing some data type. A suffix tree can -/// contain 1 or many strings, which can then be queried as one large string. -/// -/// The suffix tree is implemented using Ukkonen's algorithm for linear-time -/// suffix tree construction. Ukkonen's algorithm is explained in more detail -/// in the paper by Esko Ukkonen "On-line construction of suffix trees. The -/// paper is available at -/// -/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf -class SuffixTree { -public: - /// Each element is an integer representing an instruction in the module. - ArrayRef Str; - - /// A repeated substring in the tree. - struct RepeatedSubstring { - /// The length of the string. - unsigned Length; - - /// The start indices of each occurrence. - std::vector StartIndices; - }; - -private: - /// Maintains each node in the tree. - SpecificBumpPtrAllocator NodeAllocator; - - /// The root of the suffix tree. - /// - /// The root represents the empty string. It is maintained by the - /// \p NodeAllocator like every other node in the tree. - SuffixTreeNode *Root = nullptr; - - /// Maintains the end indices of the internal nodes in the tree. - /// - /// Each internal node is guaranteed to never have its end index change - /// during the construction algorithm; however, leaves must be updated at - /// every step. Therefore, we need to store leaf end indices by reference - /// to avoid updating O(N) leaves at every step of construction. Thus, - /// every internal node must be allocated its own end index. - BumpPtrAllocator InternalEndIdxAllocator; - - /// The end index of each leaf in the tree. - unsigned LeafEndIdx = -1; - - /// Helper struct which keeps track of the next insertion point in - /// Ukkonen's algorithm. - struct ActiveState { - /// The next node to insert at. - SuffixTreeNode *Node = nullptr; - - /// The index of the first character in the substring currently being added. - unsigned Idx = EmptyIdx; - - /// The length of the substring we have to add at the current step. - unsigned Len = 0; - }; - - /// The point the next insertion will take place at in the - /// construction algorithm. - ActiveState Active; - - /// Allocate a leaf node and add it to the tree. - /// - /// \param Parent The parent of this node. - /// \param StartIdx The start index of this node's associated string. - /// \param Edge The label on the edge leaving \p Parent to this node. - /// - /// \returns A pointer to the allocated leaf node. - SuffixTreeNode *insertLeaf(SuffixTreeNode &Parent, unsigned StartIdx, - unsigned Edge) { - - assert(StartIdx <= LeafEndIdx && "String can't start after it ends!"); - - SuffixTreeNode *N = new (NodeAllocator.Allocate()) - SuffixTreeNode(StartIdx, &LeafEndIdx, nullptr); - Parent.Children[Edge] = N; - - return N; - } - - /// Allocate an internal node and add it to the tree. - /// - /// \param Parent The parent of this node. Only null when allocating the root. - /// \param StartIdx The start index of this node's associated string. - /// \param EndIdx The end index of this node's associated string. - /// \param Edge The label on the edge leaving \p Parent to this node. - /// - /// \returns A pointer to the allocated internal node. - SuffixTreeNode *insertInternalNode(SuffixTreeNode *Parent, unsigned StartIdx, - unsigned EndIdx, unsigned Edge) { - - assert(StartIdx <= EndIdx && "String can't start after it ends!"); - assert(!(!Parent && StartIdx != EmptyIdx) && - "Non-root internal nodes must have parents!"); - - unsigned *E = new (InternalEndIdxAllocator) unsigned(EndIdx); - SuffixTreeNode *N = - new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx, E, Root); - if (Parent) - Parent->Children[Edge] = N; - - return N; - } - - /// Set the suffix indices of the leaves to the start indices of their - /// respective suffixes. - void setSuffixIndices() { - // List of nodes we need to visit along with the current length of the - // string. - std::vector> ToVisit; - - // Current node being visited. - SuffixTreeNode *CurrNode = Root; - - // Sum of the lengths of the nodes down the path to the current one. - unsigned CurrNodeLen = 0; - ToVisit.push_back({CurrNode, CurrNodeLen}); - while (!ToVisit.empty()) { - std::tie(CurrNode, CurrNodeLen) = ToVisit.back(); - ToVisit.pop_back(); - CurrNode->ConcatLen = CurrNodeLen; - for (auto &ChildPair : CurrNode->Children) { - assert(ChildPair.second && "Node had a null child!"); - ToVisit.push_back( - {ChildPair.second, CurrNodeLen + ChildPair.second->size()}); - } - - // No children, so we are at the end of the string. - if (CurrNode->Children.size() == 0 && !CurrNode->isRoot()) - CurrNode->SuffixIdx = Str.size() - CurrNodeLen; - } - } - - /// Construct the suffix tree for the prefix of the input ending at - /// \p EndIdx. - /// - /// Used to construct the full suffix tree iteratively. At the end of each - /// step, the constructed suffix tree is either a valid suffix tree, or a - /// suffix tree with implicit suffixes. At the end of the final step, the - /// suffix tree is a valid tree. - /// - /// \param EndIdx The end index of the current prefix in the main string. - /// \param SuffixesToAdd The number of suffixes that must be added - /// to complete the suffix tree at the current phase. - /// - /// \returns The number of suffixes that have not been added at the end of - /// this step. - unsigned extend(unsigned EndIdx, unsigned SuffixesToAdd) { - SuffixTreeNode *NeedsLink = nullptr; - - while (SuffixesToAdd > 0) { - - // Are we waiting to add anything other than just the last character? - if (Active.Len == 0) { - // If not, then say the active index is the end index. - Active.Idx = EndIdx; - } - - assert(Active.Idx <= EndIdx && "Start index can't be after end index!"); - - // The first character in the current substring we're looking at. - unsigned FirstChar = Str[Active.Idx]; - - // Have we inserted anything starting with FirstChar at the current node? - if (Active.Node->Children.count(FirstChar) == 0) { - // If not, then we can just insert a leaf and move too the next step. - insertLeaf(*Active.Node, EndIdx, FirstChar); - - // The active node is an internal node, and we visited it, so it must - // need a link if it doesn't have one. - if (NeedsLink) { - NeedsLink->Link = Active.Node; - NeedsLink = nullptr; - } - } else { - // There's a match with FirstChar, so look for the point in the tree to - // insert a new node. - SuffixTreeNode *NextNode = Active.Node->Children[FirstChar]; - - unsigned SubstringLen = NextNode->size(); - - // Is the current suffix we're trying to insert longer than the size of - // the child we want to move to? - if (Active.Len >= SubstringLen) { - // If yes, then consume the characters we've seen and move to the next - // node. - Active.Idx += SubstringLen; - Active.Len -= SubstringLen; - Active.Node = NextNode; - continue; - } - - // Otherwise, the suffix we're trying to insert must be contained in the - // next node we want to move to. - unsigned LastChar = Str[EndIdx]; - - // Is the string we're trying to insert a substring of the next node? - if (Str[NextNode->StartIdx + Active.Len] == LastChar) { - // If yes, then we're done for this step. Remember our insertion point - // and move to the next end index. At this point, we have an implicit - // suffix tree. - if (NeedsLink && !Active.Node->isRoot()) { - NeedsLink->Link = Active.Node; - NeedsLink = nullptr; - } - - Active.Len++; - break; - } - - // The string we're trying to insert isn't a substring of the next node, - // but matches up to a point. Split the node. - // - // For example, say we ended our search at a node n and we're trying to - // insert ABD. Then we'll create a new node s for AB, reduce n to just - // representing C, and insert a new leaf node l to represent d. This - // allows us to ensure that if n was a leaf, it remains a leaf. - // - // | ABC ---split---> | AB - // n s - // C / \ D - // n l - - // The node s from the diagram - SuffixTreeNode *SplitNode = - insertInternalNode(Active.Node, NextNode->StartIdx, - NextNode->StartIdx + Active.Len - 1, FirstChar); - - // Insert the new node representing the new substring into the tree as - // a child of the split node. This is the node l from the diagram. - insertLeaf(*SplitNode, EndIdx, LastChar); - - // Make the old node a child of the split node and update its start - // index. This is the node n from the diagram. - NextNode->StartIdx += Active.Len; - SplitNode->Children[Str[NextNode->StartIdx]] = NextNode; - - // SplitNode is an internal node, update the suffix link. - if (NeedsLink) - NeedsLink->Link = SplitNode; - - NeedsLink = SplitNode; - } - - // We've added something new to the tree, so there's one less suffix to - // add. - SuffixesToAdd--; - - if (Active.Node->isRoot()) { - if (Active.Len > 0) { - Active.Len--; - Active.Idx = EndIdx - SuffixesToAdd + 1; - } - } else { - // Start the next phase at the next smallest suffix. - Active.Node = Active.Node->Link; - } - } - - return SuffixesToAdd; - } - -public: - /// Construct a suffix tree from a sequence of unsigned integers. - /// - /// \param Str The string to construct the suffix tree for. - SuffixTree(const std::vector &Str) : Str(Str) { - Root = insertInternalNode(nullptr, EmptyIdx, EmptyIdx, 0); - Active.Node = Root; - - // Keep track of the number of suffixes we have to add of the current - // prefix. - unsigned SuffixesToAdd = 0; - - // Construct the suffix tree iteratively on each prefix of the string. - // PfxEndIdx is the end index of the current prefix. - // End is one past the last element in the string. - for (unsigned PfxEndIdx = 0, End = Str.size(); PfxEndIdx < End; - PfxEndIdx++) { - SuffixesToAdd++; - LeafEndIdx = PfxEndIdx; // Extend each of the leaves. - SuffixesToAdd = extend(PfxEndIdx, SuffixesToAdd); - } - - // Set the suffix indices of each leaf. - assert(Root && "Root node can't be nullptr!"); - setSuffixIndices(); - } - - /// Iterator for finding all repeated substrings in the suffix tree. - struct RepeatedSubstringIterator { - private: - /// The current node we're visiting. - SuffixTreeNode *N = nullptr; - - /// The repeated substring associated with this node. - RepeatedSubstring RS; - - /// The nodes left to visit. - std::vector ToVisit; - - /// The minimum length of a repeated substring to find. - /// Since we're outlining, we want at least two instructions in the range. - /// FIXME: This may not be true for targets like X86 which support many - /// instruction lengths. - const unsigned MinLength = 2; - - /// Move the iterator to the next repeated substring. - void advance() { - // Clear the current state. If we're at the end of the range, then this - // is the state we want to be in. - RS = RepeatedSubstring(); - N = nullptr; - - // Each leaf node represents a repeat of a string. - std::vector LeafChildren; - - // Continue visiting nodes until we find one which repeats more than once. - while (!ToVisit.empty()) { - SuffixTreeNode *Curr = ToVisit.back(); - ToVisit.pop_back(); - LeafChildren.clear(); - - // Keep track of the length of the string associated with the node. If - // it's too short, we'll quit. - unsigned Length = Curr->ConcatLen; - - // Iterate over each child, saving internal nodes for visiting, and - // leaf nodes in LeafChildren. Internal nodes represent individual - // strings, which may repeat. - for (auto &ChildPair : Curr->Children) { - // Save all of this node's children for processing. - if (!ChildPair.second->isLeaf()) - ToVisit.push_back(ChildPair.second); - - // It's not an internal node, so it must be a leaf. If we have a - // long enough string, then save the leaf children. - else if (Length >= MinLength) - LeafChildren.push_back(ChildPair.second); - } - - // The root never represents a repeated substring. If we're looking at - // that, then skip it. - if (Curr->isRoot()) - continue; - - // Do we have any repeated substrings? - if (LeafChildren.size() >= 2) { - // Yes. Update the state to reflect this, and then bail out. - N = Curr; - RS.Length = Length; - for (SuffixTreeNode *Leaf : LeafChildren) - RS.StartIndices.push_back(Leaf->SuffixIdx); - break; - } - } - - // At this point, either NewRS is an empty RepeatedSubstring, or it was - // set in the above loop. Similarly, N is either nullptr, or the node - // associated with NewRS. - } - - public: - /// Return the current repeated substring. - RepeatedSubstring &operator*() { return RS; } - - RepeatedSubstringIterator &operator++() { - advance(); - return *this; - } - - RepeatedSubstringIterator operator++(int I) { - RepeatedSubstringIterator It(*this); - advance(); - return It; - } - - bool operator==(const RepeatedSubstringIterator &Other) { - return N == Other.N; - } - bool operator!=(const RepeatedSubstringIterator &Other) { - return !(*this == Other); - } - - RepeatedSubstringIterator(SuffixTreeNode *N) : N(N) { - // Do we have a non-null node? - if (N) { - // Yes. At the first step, we need to visit all of N's children. - // Note: This means that we visit N last. - ToVisit.push_back(N); - advance(); - } - } - }; - - typedef RepeatedSubstringIterator iterator; - iterator begin() { return iterator(Root); } - iterator end() { return iterator(nullptr); } -}; - /// Maps \p MachineInstrs to unsigned integers and stores the mappings. struct InstructionMapper { Index: llvm/lib/Support/CMakeLists.txt =================================================================== --- llvm/lib/Support/CMakeLists.txt +++ llvm/lib/Support/CMakeLists.txt @@ -141,6 +141,7 @@ StringMap.cpp StringSaver.cpp StringRef.cpp + SuffixTree.cpp SymbolRemappingReader.cpp SystemUtils.cpp TarWriter.cpp Index: llvm/lib/Support/SuffixTree.cpp =================================================================== --- /dev/null +++ llvm/lib/Support/SuffixTree.cpp @@ -0,0 +1,210 @@ +//===- llvm/Support/SuffixTree.cpp - Implement Suffix Tree ------*- C++ -*-===// +// +// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. +// See https://llvm.org/LICENSE.txt for license information. +// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception +// +//===----------------------------------------------------------------------===// +// +// This file implements the Suffix Tree class. +// +//===----------------------------------------------------------------------===// + +#include "llvm/Support/SuffixTree.h" +#include "llvm/Support/Allocator.h" +#include + +using namespace llvm; + +SuffixTree::SuffixTree(const std::vector &Str) : Str(Str) { + Root = insertInternalNode(nullptr, EmptyIdx, EmptyIdx, 0); + Active.Node = Root; + + // Keep track of the number of suffixes we have to add of the current + // prefix. + unsigned SuffixesToAdd = 0; + + // Construct the suffix tree iteratively on each prefix of the string. + // PfxEndIdx is the end index of the current prefix. + // End is one past the last element in the string. + for (unsigned PfxEndIdx = 0, End = Str.size(); PfxEndIdx < End; PfxEndIdx++) { + SuffixesToAdd++; + LeafEndIdx = PfxEndIdx; // Extend each of the leaves. + SuffixesToAdd = extend(PfxEndIdx, SuffixesToAdd); + } + + // Set the suffix indices of each leaf. + assert(Root && "Root node can't be nullptr!"); + setSuffixIndices(); +} + +SuffixTreeNode *SuffixTree::insertLeaf(SuffixTreeNode &Parent, + unsigned StartIdx, unsigned Edge) { + + assert(StartIdx <= LeafEndIdx && "String can't start after it ends!"); + + SuffixTreeNode *N = new (NodeAllocator.Allocate()) + SuffixTreeNode(StartIdx, &LeafEndIdx, nullptr); + Parent.Children[Edge] = N; + + return N; +} + +SuffixTreeNode *SuffixTree::insertInternalNode(SuffixTreeNode *Parent, + unsigned StartIdx, + unsigned EndIdx, unsigned Edge) { + + assert(StartIdx <= EndIdx && "String can't start after it ends!"); + assert(!(!Parent && StartIdx != EmptyIdx) && + "Non-root internal nodes must have parents!"); + + unsigned *E = new (InternalEndIdxAllocator) unsigned(EndIdx); + SuffixTreeNode *N = + new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx, E, Root); + if (Parent) + Parent->Children[Edge] = N; + + return N; +} + +void SuffixTree::setSuffixIndices() { + // List of nodes we need to visit along with the current length of the + // string. + std::vector> ToVisit; + + // Current node being visited. + SuffixTreeNode *CurrNode = Root; + + // Sum of the lengths of the nodes down the path to the current one. + unsigned CurrNodeLen = 0; + ToVisit.push_back({CurrNode, CurrNodeLen}); + while (!ToVisit.empty()) { + std::tie(CurrNode, CurrNodeLen) = ToVisit.back(); + ToVisit.pop_back(); + CurrNode->ConcatLen = CurrNodeLen; + for (auto &ChildPair : CurrNode->Children) { + assert(ChildPair.second && "Node had a null child!"); + ToVisit.push_back( + {ChildPair.second, CurrNodeLen + ChildPair.second->size()}); + } + + // No children, so we are at the end of the string. + if (CurrNode->Children.size() == 0 && !CurrNode->isRoot()) + CurrNode->SuffixIdx = Str.size() - CurrNodeLen; + } +} + +unsigned SuffixTree::extend(unsigned EndIdx, unsigned SuffixesToAdd) { + SuffixTreeNode *NeedsLink = nullptr; + + while (SuffixesToAdd > 0) { + + // Are we waiting to add anything other than just the last character? + if (Active.Len == 0) { + // If not, then say the active index is the end index. + Active.Idx = EndIdx; + } + + assert(Active.Idx <= EndIdx && "Start index can't be after end index!"); + + // The first character in the current substring we're looking at. + unsigned FirstChar = Str[Active.Idx]; + + // Have we inserted anything starting with FirstChar at the current node? + if (Active.Node->Children.count(FirstChar) == 0) { + // If not, then we can just insert a leaf and move to the next step. + insertLeaf(*Active.Node, EndIdx, FirstChar); + + // The active node is an internal node, and we visited it, so it must + // need a link if it doesn't have one. + if (NeedsLink) { + NeedsLink->Link = Active.Node; + NeedsLink = nullptr; + } + } else { + // There's a match with FirstChar, so look for the point in the tree to + // insert a new node. + SuffixTreeNode *NextNode = Active.Node->Children[FirstChar]; + + unsigned SubstringLen = NextNode->size(); + + // Is the current suffix we're trying to insert longer than the size of + // the child we want to move to? + if (Active.Len >= SubstringLen) { + // If yes, then consume the characters we've seen and move to the next + // node. + Active.Idx += SubstringLen; + Active.Len -= SubstringLen; + Active.Node = NextNode; + continue; + } + + // Otherwise, the suffix we're trying to insert must be contained in the + // next node we want to move to. + unsigned LastChar = Str[EndIdx]; + + // Is the string we're trying to insert a substring of the next node? + if (Str[NextNode->StartIdx + Active.Len] == LastChar) { + // If yes, then we're done for this step. Remember our insertion point + // and move to the next end index. At this point, we have an implicit + // suffix tree. + if (NeedsLink && !Active.Node->isRoot()) { + NeedsLink->Link = Active.Node; + NeedsLink = nullptr; + } + + Active.Len++; + break; + } + + // The string we're trying to insert isn't a substring of the next node, + // but matches up to a point. Split the node. + // + // For example, say we ended our search at a node n and we're trying to + // insert ABD. Then we'll create a new node s for AB, reduce n to just + // representing C, and insert a new leaf node l to represent d. This + // allows us to ensure that if n was a leaf, it remains a leaf. + // + // | ABC ---split---> | AB + // n s + // C / \ D + // n l + + // The node s from the diagram + SuffixTreeNode *SplitNode = + insertInternalNode(Active.Node, NextNode->StartIdx, + NextNode->StartIdx + Active.Len - 1, FirstChar); + + // Insert the new node representing the new substring into the tree as + // a child of the split node. This is the node l from the diagram. + insertLeaf(*SplitNode, EndIdx, LastChar); + + // Make the old node a child of the split node and update its start + // index. This is the node n from the diagram. + NextNode->StartIdx += Active.Len; + SplitNode->Children[Str[NextNode->StartIdx]] = NextNode; + + // SplitNode is an internal node, update the suffix link. + if (NeedsLink) + NeedsLink->Link = SplitNode; + + NeedsLink = SplitNode; + } + + // We've added something new to the tree, so there's one less suffix to + // add. + SuffixesToAdd--; + + if (Active.Node->isRoot()) { + if (Active.Len > 0) { + Active.Len--; + Active.Idx = EndIdx - SuffixesToAdd + 1; + } + } else { + // Start the next phase at the next smallest suffix. + Active.Node = Active.Node->Link; + } + } + + return SuffixesToAdd; +} Index: llvm/unittests/Support/CMakeLists.txt =================================================================== --- llvm/unittests/Support/CMakeLists.txt +++ llvm/unittests/Support/CMakeLists.txt @@ -66,6 +66,7 @@ ScaledNumberTest.cpp SourceMgrTest.cpp SpecialCaseListTest.cpp + SuffixTreeTest.cpp SwapByteOrderTest.cpp SymbolRemappingReaderTest.cpp TarWriterTest.cpp Index: llvm/unittests/Support/SuffixTreeTest.cpp =================================================================== --- /dev/null +++ llvm/unittests/Support/SuffixTreeTest.cpp @@ -0,0 +1,143 @@ +//===- unittests/Support/SuffixTreeTest.cpp - suffix tree tests -----------===// +// +// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. +// See https://llvm.org/LICENSE.txt for license information. +// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception +// +//===----------------------------------------------------------------------===// + +#include "llvm/Support/SuffixTree.h" +#include "gtest/gtest.h" +#include + +using namespace llvm; + +namespace { + +// Each example vector has a unique element at the end to represent the end of +// the string + +// Tests that The SuffixTree finds a simple repetition of the substring {1, 2} +// {1, 2} twice in the provided string. +TEST(SuffixTreeTest, TestSingleRepetition) { + std::vector SimpleRepetitionData = {1, 2, 1, 2, 3}; + SuffixTree ST(SimpleRepetitionData); + std::vector SubStrings; + for (auto It = ST.begin(); It != ST.end(); It++) + SubStrings.push_back(*It); + ASSERT_EQ(SubStrings.size(), 1u); + EXPECT_EQ(SubStrings[0].Length, 2u); + EXPECT_EQ(SubStrings[0].StartIndices.size(), 2u); + for (unsigned StartIdx : SubStrings[0].StartIndices) { + EXPECT_EQ(SimpleRepetitionData[StartIdx], 1u); + EXPECT_EQ(SimpleRepetitionData[StartIdx + 1], 2u); + } +} + +// Tests that the SuffixTree is able to find the substrings {1, 2, 3} at +// at indices 0 and 3 as well as the substrings {2, 3} at indices 1 and 4. +// This test also serves as a flag for improvements to the suffix tree. +// +// FIXME: Right now, the longest repeated substring from a specific index is +// returned, this could be improved to return the longest repeated substring, as +// well as those that are smaller. +TEST(SuffixTreeTest, TestLongerRepetition) { + std::vector RepeatedRepetitionData = {1, 2, 3, 1, 2, 3, 4}; + SuffixTree ST(RepeatedRepetitionData); + std::vector SubStrings; + for (auto It = ST.begin(); It != ST.end(); It++) + SubStrings.push_back(*It); + EXPECT_EQ(SubStrings.size(), 2u); + unsigned Len; + for (SuffixTree::RepeatedSubstring &RS : SubStrings) { + Len = RS.Length; + bool IsExpectedLen = (Len == 3u || Len == 2u); + bool IsExpectedIndex; + ASSERT_TRUE(IsExpectedLen); + + if (Len == 3u) { + for (unsigned StartIdx : RS.StartIndices) { + IsExpectedIndex = (StartIdx == 0u || StartIdx == 3u); + EXPECT_TRUE(IsExpectedIndex); + EXPECT_EQ(RepeatedRepetitionData[StartIdx], 1u); + EXPECT_EQ(RepeatedRepetitionData[StartIdx + 1], 2u); + EXPECT_EQ(RepeatedRepetitionData[StartIdx + 2], 3u); + } + } else { + for (unsigned StartIdx : RS.StartIndices) { + IsExpectedIndex = (StartIdx == 1u || StartIdx == 4u); + EXPECT_TRUE(IsExpectedIndex); + EXPECT_EQ(RepeatedRepetitionData[StartIdx], 2u); + EXPECT_EQ(RepeatedRepetitionData[StartIdx + 1], 3u); + } + } + } +} + +// Tests that the SuffixTree is able to find substring {1, 1, 1, 1, 1} at +// indices 0 and 1. +// +// FIXME: Add support for detecting {1, 1} and {1, 1, 1} +TEST(SuffixTreeTest, TestSingleCharacterRepeat) { + std::vector RepeatedRepetitionData = {1, 1, 1, 1, 1, 1, 2}; + std::vector::iterator RRDIt, RRDIt2; + SuffixTree ST(RepeatedRepetitionData); + std::vector SubStrings; + for (auto It = ST.begin(); It != ST.end(); It++) + SubStrings.push_back(*It); + EXPECT_EQ(SubStrings.size(), 1u); + for (SuffixTree::RepeatedSubstring &RS : SubStrings) { + EXPECT_EQ(RS.StartIndices.size(), + RepeatedRepetitionData.size() - RS.Length); + for (unsigned StartIdx : SubStrings[0].StartIndices) { + RRDIt = RRDIt2 = RepeatedRepetitionData.begin(); + std::advance(RRDIt, StartIdx); + std::advance(RRDIt2, StartIdx + SubStrings[0].Length); + ASSERT_TRUE( + all_of(make_range::iterator>(RRDIt, RRDIt2), + [](unsigned Elt) { return Elt == 1; })); + } + } +} + +// The suffix tree cannot currently find repeated substrings in strings of the +// form {1, 2, 3, 1, 2, 3}, because the two {1, 2, 3}s are adjacent ("tandem +// repeats") +// +// FIXME: Teach the SuffixTree to recognize these cases. +TEST(SuffixTreeTest, TestTandemRepeat) { + std::vector RepeatedRepetitionData = {1, 2, 3, 1, 2, 3}; + SuffixTree ST(RepeatedRepetitionData); + std::vector SubStrings; + for (auto It = ST.begin(); It != ST.end(); It++) + SubStrings.push_back(*It); + EXPECT_EQ(SubStrings.size(), 0u); +} + +// Tests that the SuffixTree does not erroneously include values that are not +// in repeated substrings. That is, only finds {1, 1} at indices 0 and 3 and +// does not include 2 and 3. +TEST(SuffixTreeTest, TestExclusion) { + std::vector RepeatedRepetitionData = {1, 1, 2, 1, 1, 3}; + std::vector::iterator RRDIt, RRDIt2; + SuffixTree ST(RepeatedRepetitionData); + std::vector SubStrings; + for (auto It = ST.begin(); It != ST.end(); It++) + SubStrings.push_back(*It); + EXPECT_EQ(SubStrings.size(), 1u); + bool IsExpectedIndex; + for (SuffixTree::RepeatedSubstring &RS : SubStrings) { + for (unsigned StartIdx : RS.StartIndices) { + IsExpectedIndex = (StartIdx == 0u || StartIdx == 3u); + EXPECT_TRUE(IsExpectedIndex); + RRDIt = RRDIt2 = RepeatedRepetitionData.begin(); + std::advance(RRDIt, StartIdx); + std::advance(RRDIt2, StartIdx + RS.Length); + EXPECT_TRUE( + all_of(make_range::iterator>(RRDIt, RRDIt2), + [](unsigned Elt) { return Elt == 1; })); + } + } +} + +} // namespace